Math, asked by mitreshgiri66641, 11 months ago

Water is flowing at the rate of 7 metre per second through a circular pipe whose internal diameter is 2 cm into a cylindrical tank the radius of whose base is 40 determine the increase in the water level in one by two hours

Answers

Answered by ʙʀᴀɪɴʟʏᴡɪᴛᴄh
5

Answer:

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Water is flowing at the rate of 7 m/s.

o length of pipe in which the water has traveled,

h = 7(1800) = 12600m

Radius of the pipe(r)= 1cm

Radius of the cylinder(R)= 40 cm

let the height of the water in the tank H

So,

Volume of water coming from the pipe = Volume of water in the cylindrical tank.

πr^2h = πR^2h

H = {(0.01)^2 X 12600}/(0.4)^2 = 7.875m (ans)

Answered by Skyllen
0

[HeY Mate]

Answer:

Water is flowing at the rate of 7 m/s.

length of pipe in which the water has traveled,

h = 7(1800) = 12600m

Radius of the pipe(r)= 1cm

Radius of the cylinder(R)= 40 cm

let the height of the water in the tank H

So,

Volume of water coming from the pipe = Volume of water in the cylindrical tank.

πr^2h = πR^2h

H = {(0.01)^2 X 12600}/(0.4)^2 = 7.875m

I Hope It Helps You✌️

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