Question

Water is flowing at the rate of 7m/sec through a circular pipe whose internal diameter is 2 cm into a cylindrical tank the radius of whose base is 40 cm. Determine the increase in the water level in half hour

Answer 1

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Answer 2

Answer:

Water level increases to 787.5 cm in half hour.

Step-by-step explanation:

Internal diameter of pipe = 2 cm

Internal radius of pipe = 1 cm

radius of base of tank = 40 cm

Speed of water flowing out from pipe = 7 m / sec = $7\times\frac{100}{\frac{1}{60}}=7\times100\times60=42000\:cm/min$

Quantity of water flows out from pipe in 1 min = $\pi\times1^2\times42000$  cm³

Quantity of water flows out from pipe in 30 min = $\pi\times1^2\times42000\times30$

                                                                                = 3960000 cm³

let H be the height of water level in tank

Quantity of water filled in tank in 30 min = 3960000 cm³

$\pi\times40^2\times H=3960000$

$H=3960000\times\frac{7}{22\times1600}$

$H=787.5$

Therefore, Water level increases to 787.5 cm in half hour.