Question

Water is flowing in a horizontal pipe of diameter d

Answer 1

Answer: This follows from the continuity equation which is based on the law of conservation of mass

Let the area of pipe at one end be A1 and let the speed of water be v1.

Let the area of the pipe at the other end be A2 and the speed of water be v2.

density of water = d

Then mass of water flowing in every second = A1*v1*d

Mass of water flowing out every second = A2*v2*d

These two should be equal as no additional water is in this system

So A1*v1 = A2*v2

Lets come to the problem at hand

Let the current speed be v, area = pi*d^2/4

Current speed at other end = v/2, area = ?

Using our relation, we get v*pi*d^2/4 = (v/2)*area

=> area = pi*d^2/2 .. (1)

Let the new diameter be d''

Then area = pi*d''^2/4 ... (2)

Equate (1) and (2)

pi*d^2/2 = pi*d''^2/4

=> d''^2 = 2d^2

=> d'' = d√2

final answer: d*square root of 2

Please mark it as brainliest answer....

Explanation:

Answer 2

Explanation:

water is flowing in a horizontal pipe of the if you want to change the diameter of this pipe show the spends