Question

Water is flowing smoothly through a closed-pipe system. At one point the speed of the water is 3.0m//s. While at another point 1.0m higher the speed is 4.0m//s. If the pressure is 20 Kpa at the lower point, what is the pressure at the upper point? What would the pressure at the upper point be if the water were to stop flowing and the pressure at the lower point were 18 kpa?

Answer 1

Answer:

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Answer 2

Hence the pressure at the upper point is 8.2 KPa

Explanation:

Using Bernoulli equation:

P + ρgh + 1/2 ρv^2 = constant

20 KPa + 0 + 1/2 ρ x 3^2 = P + ρg x 1 + 1/2 ρ x 4^2

P = 20 kpa - ρg + 1/3 ρ (3^2 - 4^2)

P = 20 x 10^3 - 9.8 x 10^3 + 1 / 2 x 10^3 (-7)

P = ( 20 - 13.3 ) x 10^3 Pascal

P = 6.7 Kpa

18 KPa + 0 + 1/2 ρ x 0^2

P' = 18 KPa - 9.8 Kpa = 8.2 KPa

Hence the pressure at the upper point is 8.2 KPa