water is flowing steadily through a horizontal tube of non uniform cross section.if the pressure of water is 4*10^4N/mm^2 at a point where cross se ction is 0.02 m^2 velocity of flow is 2m/s what is pressure at a poin . where crossection reduces to 0.01m^2
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Explanation:
As we know
A
1
V
1
=A
2
V
2
Where A
1
=0.02 m
2
V
1
=2 m/s
A
2
=0.01 m
2
⟹0.02×2=0.01×V
2
⟹V
2
=4 m/s
Now using Bernoulli's theorem
ρ
P
1
+
2
1
V
1
2
=
ρ
P
2
+
2
1
v
2
2
⟹P
2
=P
1
+
2
ρ
1
[V
1
2
−V
1
2
]
⟹P
2
=4×10
10
+
2 1000
[2^2 −4 2]−4×10^10=3.4×10^4N/m^2
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