Water is flowing through a 200 mm diameter circular pipe having coefficient of friction, f = 0.04. The reynolds number of the flow considering viscous flow is
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Reynolds Number is a dimensionless number explaining the turbulent and laminar flow of viscous fluid through certain areas. In our case, we've a circular pipe having diameter = 200 mm= 0.2 m and coefficient of friction f = 0.04. Since water has the density ρ= 997 kg/m³.
Reynolds Number = (D*V*ρ)/μ
where; D= diameter of the circular pipe= 0.2 m
V= velocity of the fluid
ρ= density of water = 997 kg/m³
μ= friction factor = 0.04
Reynolds Number = (0.2*997*V)/0.04 = 4985 V
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Answer:
Velocity not given, so data insufficient
Explanation:
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