Question

Water is flowing through a cylindrical pipe , of internal diameter 2cm , into a cylindrical tank of base radius 40cm , at the rate of 0.4 m/s. Determine the rise in level of water in the tank in half an hour .

Answer 1

Hope it helps you
plz mark as brainliest.

Answer 2

Answer:

Water level in the tank rises by  4.5 cm.

Step-by-step explanation:

Given : Water is flowing through a cylindrical pipe , of internal diameter 2cm,into a cylindrical tank of base radius 40cm , at the rate of 0.4 m/s.

To find : Determine the rise in level of water in the tank in half an hour ?

Solution :

Internal diameter of the pipe = 2 cm

Radius of the pipe = 1 cm

Area of the base of the pipe $A=\pi r^2$

Area of the base of the pipe $A=\pi 1^2=\pi$

Rate of flow of water = 0.4 m/s

                                   = 0.4×100=40 cm/s

Volume of water that flows in 1 sec.=Area of the base of pipe × rate of water flow

$V=\pi \times 40=40\pi cm^3$

Volume of water collected in the cylindrical tank in half an hour.

$v=4\pi\times 30\times 60$

Let rise in the water level in the water tank be h cm.

The volume of water collected in the cylindrical tank in half an hour.

$V=\pi \times 40^2\times h$

Equating the volume of water in cylindrical tank,

$4\pi\times 30\times 60=\pi \times 40^2\times h$

$7200= 1600\times h$

$h=\frac{7200}{1600}$

$h=4.5cm$

Water level in the tank rises by  4.5 cm.