Question

Water is flowing through a cylindrical pipe of internal diameter 2cm, into a

cylindrical tank of base radius 40 cm at the rate of 0.7m/sec. By how

much will the water rise in the tank in half an hour?
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Answer 1

Answer:

hope this will help you....

Answer 2

Answer:

Water is flowing through a cylindrical pipe of internal diameter 2cm, into a cylindrical tank of base radius 40 cm at the rate of 0.7m/sec.

Volume of pipe

$\pi \: {r}^{2} h = \frac{22}{7} \times 1 \times 70 = 220 \: {cm}^{2}$

So, Water flow for 30 minutes,

$220 \times 30 \times 60 = 396000$

Now the height of tank to be filled,

$\pi \: {r}^{2} h = \frac{22}{7} \times 40 \times 40\times \: h = 396000$

$\frac{22}{7} \times 40 \times 40\times \: h = 396000 \\ h = \frac{396000 \times 7}{22 \times 1600} = 78.75 \: cm$

The water rise in the tank to 78.75 cm in half an hour.