Question

Water is flowing through a cylindrical pipe of internal diameter 2 cm into a cylindrical tank of base radius 40 cm at the rate of 0.7m/sec .By how much will the water rise in the tank in half an hour ?

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Answer 1

Answer:

I am explaining this answer in short

r of pipe = 2/2 = 1cm = 1/100m

r of cylinder = 40cm = 40/100m

speed of water flowing From pipe = 0.7m/sec

means 0.7 m of water flowing in 1 sec

therefore in 30 minute water will flow = 0.7 × 60 × 30

= 1260m

that means length( height of pipe) = 1260m

volume of water flowing in pipe

pie × r2 × h

pie × 1/100 × 1/100 × 1260

= pie × 126/1000m3 equation ( 1 )

volume of cylinder = pie × r2 × h

= pie × 4/10 × 4/10 × h

= 16pie×h/100 equation ( 2 )

by ( 1 ) and ( 2 )

pie × 126/1000 = 16pie × h/100

pie × 126/1000 × 100/16pie = h

h = 126/160

in cm,

126× 100/160

= 1260/160

h = 78.75

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Answer 2

Answer:

refer these 3 images in the attachment pls ...