Question

Water is flowing through a cylindrical pipe of internal diameter 2cm, into a

cylindrical tank of base radius 40 cm at the rate of 0.7m/sec. By how

much will the water rise in the tank in half an hour?
​

Answer 1

Answer:

H =78.75 cm.

Step-by-step explanation:

Question:

Water is flowing through a cylindrical pipe of internal diameter 2cm, into a cylindrical tank of base radius 40 cm at the rate of 0.7m/sec. By how much will the water rise in the tank in half an hour?

To find

how much will the water rise in the tank in half an hour?

Solution:

For pipe, r = 1cm

Length of water flowing in 1 sec,

h = 0.7m = 7cm Cylindrical Tank,

R = 40 cm,

rise in water level = H

Volume of water flowing in 1 sec = πr2h = π x 1 x 1 x 70 = 70π

Volume of water flowing in 60 sec = 70π x 60

Volume of water flowing in 30 minutes = 70π x 60 x 30

Volume of water in Tank = πr2H = π x 40 x 40 x H

Volume of water in Tank = Volume of water flowing in 30 minutes π x 40 x 40 x H = 70π x 60 x 30 H = 78.75cm

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