Math, asked by Sreekala4mt, 4 months ago

Water is flowing through a cylindrical pipe of internal diameter 2cm, in to a cylindrical tank of base radius 40cm at the rate of 0.7m per second . by how much will the water rise in the tank in half an hour?
just gave me a simple and easily understanding answer as it is a 5 mark question

Answers

Answered by mokshit24
1

Answer:

For pipe, r = 1cm Length of water flowing in 1 sec, h = 0.7m = 7cm Cylindrical Tank, R = 40 cm, rise in water level = H Volume of water flowing in 1 sec = πr2h = π x 1 x 1 x 70 = 70π Volume of water flowing in 60 sec = 70π x 60 Volume of water flowing in 30 minutes = 70π x 60 x 30 Volume of water in Tank = πr2H = π x 40 x 40 x H Volume of water in Tank = Volume of water flowing in 30 minutes π x 40 x 40 x H = 70π x 60 x 30 H = 78.75cm

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