Question

Water is flowing through a cylindrical pipe of internal diameter 4 cm into a cylindrical tank
of base radius 20 cm at the rate of 0.6 m/s. Find by how much height, the water in the tank
will rise in half an hour.​

Answer 1

Answer:

For pipe, r = 1cm Length of water flowing in 1 sec, h = 0.7m = 7cm Cylindrical Tank, R = 40 cm, rise in water level = H Volume of water flowing in 1 sec = πr2h = π x 1 x 1 x 70 = 70π Volume of water flowing in 60 sec = 70π x 60 Volume of water flowing in 30 minutes = 70π x 60 x 30 Volume of water in Tank = πr2H = π x 40 x 40 x H Volume of water in Tank = Volume of water flowing in 30 minutes π x 40 x 40 x H = 70π x 60 x 30 H = 78.75cm...

Answer 2

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➵ For pipe, r = 1cm Length of water flowing in

➵ 1 sec, h = 0.7m = 7cm Cylindrical Tank, R = 40

➵ cm, rise in water level = H Volume of water

➵ flowing in 1 sec = πr2h = π x 1 x 1 x 70 = 70π

➵ Volume of water flowing in 60 sec = 70π x 60

➵ Volume of water flowing in 30 minutes = 70π

➵ x 60 x 30 Volume of water in Tank = πr2H = π x

➵ 40 x 40 x H Volume of water in Tank = Volume

➵of water flowing in 30 minutes π x 40 x 40 x H

➵ = 70π x 60 x 30 H = 78.75cm

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