Question

Water is flowing through a cylindrical pipe of internal diameter 2cm, into a

cylindrical tank of base radius 40 cm at the rate of 0.7m/sec. By how

much will the water rise in the tank in half an hour?​

Answer 1

Answer:

For pipe, r = 1cm  

Length of water flowing in 1 sec, h = 0.7m = 7cm  

Cylindrical Tank, R = 40 cm, rise in water level = H  

Volume of water flowing in 1 sec = πr2h = π x 1 x 1 x 70  

= 70π  

Volume of water flowing in 60 sec = 70π x 60  

Volume of water flowing in 30 minutes = 70π x 60 x 30  

Volume of water in Tank = πr2H = π x 40 x 40 x H  

Volume of water in Tank = Volume of water flowing in 30 minutes  

π x 40 x 40 x H = 70π x 60 x 30  

H = 78.75cm

Step-by-step explanation:

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