Water is flowing through a cylindrical pipe of internal diameter 2cm, into a
cylindrical tank of base radius 40 cm at the rate of 0.7m/sec. By how
much will the water rise in the tank in half an hour?
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Answer:
3.15m
Step-by-step explanation:
length of water flowed in 1 hour = 0.7×3600 =2520m
volume of water flowned = cross-section area ×length
= (2×3.14÷10^4) × 2520
=1.58 L
volume of water contained in tank = 1.58 L
=> 3.14×(0.4)²×height = 1.58
=> height = 1.58÷[3.14×(0.4)²]
=> height = 3.15 m
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