Question

Water Is Flowing Through a Cylindrical Pipe Of Internal Diameter 2 cm, Into a Cylindrical Tank Of Base Radius
40 cm At The Rate Of 0.7 m/sec. By How Much Will The Water Rise In The Tank In Half An Hour?

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Radius of cylindrical pipe r=1cm

Radius of cylindrical tank R=40cm

water is flowing through a cylindrical pipe

into cylindrical tank at the rate of 40cm/ s

length of water through pipe , I=rate ×

time taken

= 40cm/ s× 1/2hour

= 40cm/ s ×30×60

= 40× 1800cm

= 72000cm

Now volume of water flows through pipe

= volume of water rise in cylindrical tank

or, pi r square ×I= pi r square × h

or , h= 72000cm cube = 1600 cm square× h

h= 720/16cm= 45cm

Hence the water rise in the yank of half an hour is 45 cm.

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