Question

Water is flowing through a horizontal pipe of non uniform cross section. The speed of water is 30cm/s at a place where pressure is 10 cm of water

Answer 1

"We can solve this question by using Bernoulli's theorem.

Which is,

$P + \frac {\rho v^2} {2} +\rho hg = constant$

Where,

P = pressure

$\rho = density of the liquid$

v = velocity

h = height

g = acceleration due to gravity

Since it is a horizontal pipe, the height (potential energy part becomes zero)

Now the equation can be changed as below,

but we know that, pressure (P) = ⍴hg

$\frac {\rho v^2} {2} +\rho hg = constant$

$\frac {v^2} {2} + hg = constant$

substituting the given values in the above equation,

$\Rightarrow h_1g + \frac {1} {2} v_1^2 = h_2 g + \frac {1} {2} v^2_2$

$\Rightarrow 10\times10 + \frac {1} {2} \times(30)^2 = 5\times10 + \frac {1} {2} \times (v_2^2)$

$\Rightarrow 100 + 450 = 50 + (\frac {v_2^2} {2})$

$\Rightarrow 500 = \frac {v_2^2} {2}$

$\Rightarrow 1000 = v_2^2$

$\Rightarrow 31.62 \frac { cm }{ s } = v_2$

Therefore, speed of water $= 31.62 \frac { cm }{ s }$ "

Answer 2

Answer:

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