water is flowing through a pipe with a velocity of 0.212m/s and 0.477m/s at section 1-1 (bottom end) and section 2-2(upper end) respectively as shown in figure-03. The pressure at section 1-1 is 350KN/m². Determine pressure at section 2-2, if the difference in elevation between section 1-1 and section 2-2 is 83.5ft.
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Using equation of continuity, we can find the velocity at another point. we have
a
1
v
1
=a
2
v
2
⇒(2×10
−2
)×2=0.01×v
2
⇒v
2
=4m/s
According to Bernoulli's theorem, for water at same height
ΔP=
2
ρ(v
1
2
−v
2
2
)
⇒ΔP=
2
1000×(2
2
−4
2
)
=−6000Pa
⇒P
2
−P
1
=−6000Pa
⇒P
2
−40000=−6000Pa
⇒P
1
=34000Pa=3.4×10
4
Pa
a
1
v
1
=a
2
v
2
⇒(2×10
−2
)×2=0.01×v
2
⇒v
2
=4m/s
According to Bernoulli's theorem, for water at same height
ΔP=
2
ρ(v
1
2
−v
2
2
)
⇒ΔP=
2
1000×(2
2
−4
2
)
=−6000Pa
⇒P
2
−P
1
=−6000Pa
⇒P
2
−40000=−6000Pa
⇒P
1
=34000Pa=3.4×10
4
Pa
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