Water is mixed with an alcohol-water solution with initial alcohol to water ratio a:5 such that the final solution contains 10a% alcohol. If they were mixed in the ratio 1:4, what is the value of a?
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Given:
Initial alcohol to water ratio a:5 such that the final solution contains 10a% alcohol.
If they were mixed in the ratio of 1:4
To find:
What is the value of a?
Solution:
Percentage concentration of alcohol in alcohol-water solution
= 100a/(a + 5) %
By Alligation method:
0% 100a/(a + 5) %
10a%
100a/[(a + 5) - 10a] 10a
∴ 100a/(a + 5) - 10a: 10a = 1 : 4
10/(a + 5) - 1 = 1/4
10/(a + 5) = 5/4
2(a + 5) = 1/4
8 = a + 5
a = 8 - 5
a = 3
Therefore, the value of a is 3
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