Question

WATER IS POURING INTO A CUBOIDAL RESERVOIR AT THE RATE OF 60 LITRES PER MINUTE.IF THE VOLUME OF RESERVOIR IS 108m3.FIND THE NUMBER OF HOURS IT WILL TAKE TO FILL THE RESERVOIR.

Answer 1

1m3=1000 L
Therefore 60L=0.06m3
No. of minutes taken= 108/0.06
                                 = 1800
therefore no. of hours = 1800/60
                                   = 30 hours

Answer 2

Firstly you need to convert the 60 litres per minute into m^3 per hour. 

In one m^3 there are 1000 litres. 

Therefore, 60 / 1000 = 0.06 m^3 / minute. 

So in one hour: 60 x 0.06 = 3.6 m^3 / hour 

So time taken equals volume of reservoir, divided by the flow rate: 

108 (m^3) / 3.6 (m^3/hour) = 30 hours