WATER IS POURING INTO A CUBOIDAL RESERVOIR AT THE RATE OF 60 LITRES PER MINUTE.IF THE VOLUME OF RESERVOIR IS 108m3.FIND THE NUMBER OF HOURS IT WILL TAKE TO FILL THE RESERVOIR.
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Answered by
20
1m3=1000 L
Therefore 60L=0.06m3
No. of minutes taken= 108/0.06
= 1800
therefore no. of hours = 1800/60
= 30 hours
Therefore 60L=0.06m3
No. of minutes taken= 108/0.06
= 1800
therefore no. of hours = 1800/60
= 30 hours
Answered by
12
Firstly you need to convert the 60 litres per minute into m^3 per hour.
In one m^3 there are 1000 litres.
Therefore, 60 / 1000 = 0.06 m^3 / minute.
So in one hour: 60 x 0.06 = 3.6 m^3 / hour
So time taken equals volume of reservoir, divided by the flow rate:
108 (m^3) / 3.6 (m^3/hour) = 30 hours
In one m^3 there are 1000 litres.
Therefore, 60 / 1000 = 0.06 m^3 / minute.
So in one hour: 60 x 0.06 = 3.6 m^3 / hour
So time taken equals volume of reservoir, divided by the flow rate:
108 (m^3) / 3.6 (m^3/hour) = 30 hours
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