Question

Water is pouring into a cuboidal reservoir at the rate of 60 litres per minute. If the volume of the reservoir is 108m3, find the number of hours it will take to fill the reservoir.

Answer 1

Answer:

\underline{Relationship }

Relationship

1 m³ = 1 ml

1 litre = 1000 cm³

1 m³ = 1000000 cm³ = 1000 litres

If,

1 m³ = 1000 litres

so,

capacity of reservoir = 108 × 1000 = 108000 litres

.

Water is being poured at rate of 60 litre per minute.

= (60 × 60) = 3600 litre per hour

Number of hours water will take to fill the reservoir

= \frac{108000}{3600}

3600

108000

= 30 hours

Hence,

it will take 30 hours to fill the reservoir

Answer 2

${\huge{\underline{\underline{\sf{\red{Question :-}}}}}}$

Water is pouring into a cuboidal reservoir at the rate of 60 litres per minute. If the volume of the reservoir is 108 m^3 , find the number of hours it will take to fill the reservoir.

${\huge{\underline{\underline{\sf{\red{Solution :-}}}}}}$

Hence,

$Volume \: of \: the \: reservoir = 108 \: {m}^{3}$

$= 108 \times 1000 \: l \: \: \: (∴ \: 1 \: {m}^{3} = 1000 \: l)$

Rate at which water is pouring

= 60 l per minutes

Therefore ,

Time taken to fill the reservoir

$= \frac{Volume \: of \: the \: reservoir }{Rate \: of \: filling \: the \: reservoir }$

$= \frac{10800}{60} \: minutes \: = 1800 \: minutes$

$= \frac{1800}{60} \: hours \: = 30 \: hours$

(∴ 1 hour = 60 minutes )