Question

WATER IS POURING INTO A CUBOIDAL RESERVOIR AT THE RATE OF 60 LITRES PER MINUTE.IF THE VOLUME OF RESERVOIR IS 108m3.FIND THE NUMBER OF HOURS IT WILL TAKE TO FILL THE RESERVOIR.

Answer 1

1m^3 = 1000 litres
108 m^3 = 108000 litres

Rate is 60l/min

Total time taken will be 108000/60 = 1800 minutes which is 1800/60 = 30 hours

Answer 2

Given:

• Volume of the reservoir = $108 \: m^{2}$

• Rate of pouring water into cuboidal reservoir = 60 litre / minute

To Find:

Time required to fill the reservoir.

Solution:

As per the given information,

Given, volume of the reservoir = $108 \: m^{2}$

Rate of pouring water into cuboidal reservoir = 60 litre / minute

$\implies 60/1000 \: m^{3}$ per minute

Since 1 litre = $\frac{1}{1000} \: m^{3}$

$:\implies \frac{60 \times 60}{1000} m^{3}$ per hour

Therefore,

$\frac{60 \times 60}{1000} m^{3}$ water filled in reservoir will consume = 1 hour

Then,

$1 \: m^{3}$ water filled in a reservoir will consume = $\frac{1000}{60\times 60}$  hours

Hence, $108 \: m^{3}$ water filled in a reservoir will take = $\frac{108 \times 1000}{60 \times 60}$

$:\implies \boxed{30 \: hours}$

Hence, it will take 30 hours to fill the reservoir.