Water is supplied to a city population for general use from a river through a cylindrical pipe. the radius of the cross section of pipe is 10cm. the speed of water through the pipe is 18km per hour. find the quantity of water in litres which is supplied to the city in 2 hours.
Here, I have the solution.. but I have a different query... Why do we take out the area, here and not the CSA?
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radius of pipe = 10 cm
area of cross section = λr²
= 22/7 x 10 x 10
= 2200/7
speed of water through the pipe = 18 km/h
length of column of water flown in 2 hr = 18 x 2 = 36 km or 360000cm
volume of water flown = area x length of column of water flown
= 2200/7 x 360000
= 792 x 10⁷ cm3
or 792 x 10⁴l
they asked to find the quantity of water in liters which is supplied which is actually equal to the VOLUME OF WATER FLOWED TO THE PIPE IN 2HRS .Since volume of a cylindrical pipe is AREA * HEIGHT (πr^2h) we find the area . And the height is actually the distanced traveled by the water. Where D = S*T.
area of cross section = λr²
= 22/7 x 10 x 10
= 2200/7
speed of water through the pipe = 18 km/h
length of column of water flown in 2 hr = 18 x 2 = 36 km or 360000cm
volume of water flown = area x length of column of water flown
= 2200/7 x 360000
= 792 x 10⁷ cm3
or 792 x 10⁴l
they asked to find the quantity of water in liters which is supplied which is actually equal to the VOLUME OF WATER FLOWED TO THE PIPE IN 2HRS .Since volume of a cylindrical pipe is AREA * HEIGHT (πr^2h) we find the area . And the height is actually the distanced traveled by the water. Where D = S*T.
pinksparkles22:
Yeah, I got it.. Thanks :)
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