Water is the flowing at the rate of 2.5km/h through acylindrical pipe into acylindrical tank.the radius of whose base is 40cm..if the increase in the level of water in the tank.in half an hour is 3.15m.Find the interna diamter of the pipe
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given increase in height of tank = 3.15 m
Therefore increase in 1 hour = 6.30 m
volume of pipe = volume of tank
π r² 2500 = π (4/10)² (6.30)
r = 16x630/2500x100x100
∴ diameter of pipe = (8/5000) (√630) m
Therefore increase in 1 hour = 6.30 m
volume of pipe = volume of tank
π r² 2500 = π (4/10)² (6.30)
r = 16x630/2500x100x100
∴ diameter of pipe = (8/5000) (√630) m
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