Question

Water of mass 200 g and temperature 30 °C is
taken in a copper calorimeter of mass 50
and temperature 30 °C. A copper sphere of
mass 100 g and temperature 100 °C is released
into it. What will be the maximum
temperature of the mixture? [c (water) =
1 cal/g.°C,c (copper) = 0.1 cal/g °C



Plz help me ​

Answer 1

heat lost by copper sphere

heat lost by copper sphere = heat gained by water + heat gained by calorimeter

100(0.1)(100-x) = 200(1)(x-30) + 50(0.1)(x-30)

1000 - 10x = 200x - 6000 + 5x - 1500

215x = 8500

x = 39.53

Answer 2

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