Water pours out at the rate of Q from a tap, into a cylindrical vessel of radius r. Find the rate at which the height of water level rises when the height is h.
[Kindly solve by calculus]
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Answer:
Explanation: :
If V be the volume of liquid in the cylinder, at a height h of the water level, then V=πr2h.
Differentiating both sides w.r.t time t, we get
dVdt=πr2dhdt
⇒Q=πr2dhdt or dhdt=Qπr2
Note that dV/dt represents the rate at which the volume of liquid in the cylinder increases, which is same as the rate of pouring of water through the tap.
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