Question

water rises in a capillary tube to a height of 2 cm.In another capillary tube whose radius is one third of it,how much will the water rise ?If the first capillary tube is inclined at an angle 60 with the vertical , then what will be the position of water in the tube?

Answer 1

We know , Formula for height of liquid column in a capillary tube  is

h= 2Tcos(0)/pgr

Here h is inversely proportional to its radius, r.

so, the relation between heights and radii are given by,  

h1r1=h2r2

r2=r1/3

h1=2

h2=h1r1/r2

=2xr1/(r1/3)

=6

h 2 =6 cm

water rises to 6 cm if dia is reduced to  1/3  

Case 2:

Let l be the length up to which water rises in the tube in inclined position, then vertical height h must be the 2 cm  

so, l = 2/cos60°

= 2/(0.5)

=4 cm

Answer 2

The h is the height of the liquid column that is placed in a capillary will be inversely proportional to the r.

Here r will be the radius.

However, if we have to compare the total height of the same liquid that is in two capillary tubes then we will follow:

h1f1 = h2f2

h2 = h1 (f1/f2)

h2 = 2 * 3

h2 = 6cm