Water rises in a capillary tube to a height of 2 cm. In another capillary tube whose radius is one third of it, how much the water will rise? If the first capillary tube is inclined at an angle of 60° with the vertical then what will be the position of water in the tube.
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Answer:
Explanation:
Height of capillary tube (h) = 2cm (Given)
Angle inclination = 60° (Given)
Height of liquid column in a capillary tube is = h = 2Tcos(0)/pgr
where h is inversely proportional to the radius, r.
The relation between heights and radii is given by -
h1r1=h2r2
r2 = (1/3)r and h1=2cm
h2 = h1 (r1/r2)
= 2 x r1 /(r1/3)
=6
h2 =6 cm
Let l be the length up to which water rises in the tube in inclined position, then vertical height h must be the 2 cm
so, l = 2/cos60°
= 2/(0.5)
=4 cm
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