Water runs into a tank of diameter 4 and height 5 metres . Acircular holr ehose diameter is 4 cm at 1/10 m per second. Find the time requirrd for tge tabk to be filled up.
Answers
Answered by
0
Let tank filled x sec.
Water is flowing at the rate of 1/10 m/s.
Length of the water coloumn in x sec = x/10 m
The water column forms a cylinder of of radius
r = 2 cm = 0.02 m and h (length) = x/10 m
Volume of water that flows in the tank in x sec =  r2 h = (22/7 * 0.02 * 0.02 * x/10 ) m3
Therefore
Volume of tank = Volume of the water flows in the cistern in x hours
22/7 * 2 * 2 * 5 = 22/7 * 0.02 *0.02 * x/10
= 500000 sec
= 500000 / 60 * 60 = 138.9 or 139 hours
Water is flowing at the rate of 1/10 m/s.
Length of the water coloumn in x sec = x/10 m
The water column forms a cylinder of of radius
r = 2 cm = 0.02 m and h (length) = x/10 m
Volume of water that flows in the tank in x sec =  r2 h = (22/7 * 0.02 * 0.02 * x/10 ) m3
Therefore
Volume of tank = Volume of the water flows in the cistern in x hours
22/7 * 2 * 2 * 5 = 22/7 * 0.02 *0.02 * x/10
= 500000 sec
= 500000 / 60 * 60 = 138.9 or 139 hours
Similar questions