Question

Waterfall height from top to bottom 490 m joule is 4200j/kcal

Answer 1

Free fall in vacuum -

E = mgh = 1 kg * 9.81 m/sec^2 * 500 m = 4,905 Joules/litre

The specific heat of liquid water is -

4,180 Joules/(kg K)

So, this is 4905/4180 = 1.173445 degress C, or K.