Question

Waterfall over a fall of 30 metre at a rate of4520^6 kg /min the power generated is

Answer 1

Answer:

P(ower) = E / t

P = m g h / t     where m g h is the potential energy of the water

P = 4.52E9 kg * 9.8 m/s^2 * 30 m / (1 min * 60 sec/min)

P = 2.21 E10 kg m^2 / s^3 = 2.21 E10 J/s = 2.21 E10 Watts