Waterfalls from a height 500m what is the rise in temperatureof water at botton if whole energy remains in the water?
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Swayze (luv)
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Here is your answer
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J = joules
L = liquid
° = degrees
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E =mgh = 1 kg x 9.81 m/sec^2 x 500 m
= 4905 J/ L
You know,
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The specific heat of liquid water is
= 4180 Joules/(kg K)
So You can divide the joules liquid & specific heat water .
= 4905/4180
= 1.173445 ° C
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