Watermelon A is 2 kg lighter than watermelon B and it weighs one fifth of the weight of watermelon C. Watermelons A and C together are 3 times as heavy as watermelon B. How heavy is each watermelon?
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Given: Watermelon A is 2 kg lighter than watermelon B and it weighs one fifth of the weight of watermelon C. Watermelons A and C together are 3 times as heavy as watermelon B.
To find: How heavy is each watermelon?
Solution:
- Let the first watermelon be x, second be y and third be z.
- According to the question, we have:
x + 2 = y .................(i)
5x = z ................ (ii)
x + z = 3y .................(iii)
- Now solving them, we get:
- Putting Putting i, ii in iii, we get:
x + 5x = 3(x+2)
6x = 3x + 6
3x = 6
x = 2
- Putting x = 2 in i and ii, we get:
y = 2 + 2 = 4
z = 5(2) = 10
Answer:
So the first watermelon weigh 2 kg, second weigh 4 kg and third watermelon weigh 10 kg.
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