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The displacement-equation of a y=1.5 sin (6280t-12.56x). Determine the frequency of the wave.
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Answer:
Comparing with the standard equation of a progressive wave.
We have, a=1.5cm,ω=328 rad s−1,k=1.27 rad cm−1
Therefore, amplitude=1.5cm
Angular frequency (ω)=2πT
328=2πT
⇒T=2π328=2×3.14328=0.019s
Frequency v=1T=3282π=3286.28=52.23Hz
Further K=1.27 rad cm−1
⇒λ=2π1.27=2×3.141.27=4.94cm
Hope it helps you...
vaishnavishahi20:
I had asked for frequency ie:n, and the answer is 1000Hz I only want the solution
if u knew the answer, then y did u post the question? Hey, was it to test our knowledge?
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