Question

wave number for series limit of paschen series of hydrogen atom is?

Answer 1

"For a hydrogen molecule, made out of a circling electron bound to a core of one proton, an ionization vitality of2.18 × 10 −18 joule (13.6 electron volts) is required to drive the electron from its most reduced vitality level completely out of the iota.

λ=8205.8A

The Rydberg Expression gives:

1λ=R[1n21−1n22]

R is the Rydberg Constant = 1.097×10−2nm−1

n1=2

n2=4

These allude to the guideline quantum quantities of the vitality levels which the electrons move from.

1λ=1.097×10−2[0.25−0.0625]=0.00206nm−1

λ=485.4nm

The sub - shells d and p given are unimportant to the question as, in the hydrogen particle, the sub - shells inside a vitality level are deteriorate (of a similar vitality)."

Answer 2

$\huge \tt \: \: Lamda \: = 485.4$