Question

wave number of first line in balmer series of Be3+​

Answer 1

The wave number of the first line of Balmer series of hydrogen is 15200 cm−1.

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Answer 2

Answer:

The correct answer for the wave number in first line of balmer series  is $(v)_{Be^{3+} }$ = $2.43*10^5 cm^-^1$ .

Explanation:

The wave number of fan electromagnetic field is equal to the 2 Pi divided by the wavelength. Wave number is expressed in the reciprocal meter.

Balmer Series is a series of spectral emission lines of hydrogen atom that results from the electron transmission from higher level to low energy level.

For any particular series of line. The wave number is proportional to the Z square, which is the atomic number.

AS equation we can write that ,

V ∝ $Z^2$

where ,

V = wave number

Z = atomic number

now ,

V(Be) = 16v (H)

V(Be) = 16 (15200$cm^-^1$)

V(Be) =  $2.43*10^5 cm^-^1$

Hence we can say that ,the wave number in first line of balmer series  is $(v)_{Be^{3+} }$ = $2.43*10^5 cm^-^1$ .

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