Question

Wavelenght of proton accelerated through v volts.

Answer 1

Answer:

The de Broglie wavelength of a particle is inversely proportional to its momentum p = m v; since a proton is about 1800 times more massive than an electron, its momentum at the same speed is 1800 times that of an electron, and therefore its wavelength 1800 times smaller.

 

    λ $= \frac{h}{mv}$