Chemistry, asked by sumalyadas34, 11 months ago

Wavelength of 1st Balmer line in Hydrogen spectra =6560Armstrom. Express it in nm.

Answers

Answered by tusharraj77123
0

Answer:

The 3→2 transition depicted here produces H-alpha, thefirst line of the Balmer series. For hydrogen (Z = 1) this transition results in a photon of wavelength 656 nm (red).

Explanation:

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Answered by mvpkchoudary
0

Answer:

1 Armstrom=1/10nm.

=6560×1/10=656.0

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