Chemistry, asked by Tanay2031, 11 months ago

wavelength of first spectral line in the balmer series is 656 angstroms calculate the wavelength of second spectral line

Answers

Answered by khavyagopan

2

Answer

1λHz=RZ2H[14−19]=R(1)2[536]

1λHe=RZ2He[14−116]=R(4)2[316]

λHzλHe=14[163×536]=527

λHe=527×6561=1215Å

hope it helps.......

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