Question

Wavelength of high energy transition of H–atoms is 91.2nm. Calculate the corresponding wavelength of He atoms.

Answer 1

Answer:

22.8nm

Explanation:

wave length o hydrogen =91.2 nm

higher energy transition

n1=1  n2= ininity

wave length of helium = ?

1 / lamda =RZ^2 (1/n1^2 -1/n2^2)

=R(2^2) (1-0)

=4R

1/LAMDA=4R

lamda =1/4r

1/4 . 91.2 nm

22.8 nm