Question

wavelength of photon X 4000A and that of Y is 6000A.Then find the ratio of photon X to photon Y ?​

Answer 1

Answer:

Vs1 = hc/e [1/λ1 − 1/λ0]

Vs2 = hc/e [1/λ2 - 1/λ0]

Vs2 - Vs1 = hc/e [1/λ2 - 1/λ1)

=[(6.624×10^-34×3×10^8)(1/3600-1/4000)]/1.6×10^-19

$= {10}^{10}$

= 0.02 V on simplification