Question

Wavelength of two notes in air 80/195 and 80/193 each note produces 5 beats per second with a third note of fixed frequency calculate the velocity of sound in air

Answer 1

Answer:

 let lambda 1= > T1 and lambda 2 = > T2 

 given T1 =( 90/175 ) m         and T2 = > (90/173) m 

if F1 and F2 are the corrosponding frequencies and v is the velocity of sound in air , we have 

v = > F1T1        and v = > F2T2 

F1 = > v / T1      and F2 = > v/T2

since T1 < T2 we must have F1 > F2 

if F is the frequency of the third note , then 

F1 - f = > 4     and f - F2 = > 4 

we get F1- F2  = > 8 

v/T1    -    v/T2 = > 8 

v{ 175/90 -  173/90 }  => 8 

v ×2/90 = > 8 we get v = > 360 m /s   is our required answer 

Hopes this will help you pari !

@ 10 class Phanindra Tagore Reddy     :-)

Explanation:

Answer 2

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