Question

wavelengths of different radiation are given below: a = 350 nm b = 350 um c = 3.5 nm and d = 35 A .. arrange these radiation in order of their increasing energies​

Answer 1

Given:

Wavelengths of different radiation are given below: a = 350 nm b = 350 um c = 3.5 nm and d = 35 A°.

To find:

Arranging the radiation in order of their increasing energy.

Calculation:

General expression of energy of electromagnetic waves is ;

$\sf{E = planck \: const. \times frequency}$

$= > \sf{E = h f}$

$= > \sf{E = h \times \dfrac{c}{ \lambda} }$

$\boxed{ = > \sf{E = \dfrac{hc}{ \lambda} }}$

For constant h and c ;

$\boxed{ \sf{E \propto \dfrac{1}{ \lambda} }}$

So, higher wavelength would correspond to lower the energy of radiation.

$a = 350 \: nm = 0.35 \: \mu m \\ b = 350 \: \mu m \\ c = 3.5 \: nm = 0.0035 \: \mu m \\ d = 35 \: ang. = 0.0035 \: \mu m$

Required arrangement ;

$\boxed{ \sf{b < a < c = d}}$

Answer 2

Answer:

given =

a = 350 nm

b = 350 nm

c=3.5 nm

d = 35A

to find =  arranging order of increasing energies

solution =  

we know that ,

E = h×f

were f= c/λ

so we can write above equation

E=  h ×c/λ  

from above equation we can say that  energy and wavelength have inverse relation

a = 350 nm = 0. 35 μm

b= 350 μm

c= 3.5 nm=  0.0035μm

d = 35nm = 0.0035 μm

final answer is

b < a ,< c= d