wavelenth of a photon having an energu of 2 eV will be.....
Answers
Answered by
0
hc=12400ev/A
energy = 2ev
as energy =HC/lambda
2=12400/lambda
wave length is approx 6200 angstroms
energy = 2ev
as energy =HC/lambda
2=12400/lambda
wave length is approx 6200 angstroms
p6781584pbck8a:
hc=22400 .....??
Similar questions