Question

Waves emitted by two identical sources produces intensity of K unit at a point on screen where path difference between these waves is lamda. Calculate the intensity at that point on screen at which path difference is (lamda)/(4)

Answer 1

Answer:

For path difference λ,

phase difference =2πrad.

For path difference 4λ,

phase difference =2πrad.

As K=4I0 so intensity at given point where path difference is 4λ

K′=4I0cos2(4π)                (cos4π=cos45∘)

K′=2I0=2K.