Question

Way to do this question

Answer 1

Answer:

Required force is 124,550 N.

Explanation:

Here,

Mass of the car ( m ) : 200 kg

Distance covered ( d ) : 8 m

Initial velocity ( u ) : 6 m / s

Final velocity ( v ) : 100 m / s.

We know,

= > d = ut + 1 / 2 at^2

= > 8 m = ( 6 m / s )t + 1 / 2 [ { ( v - u ) / t x t^2 ]

= > 8 m = 6t m / s + 1 / 2 ( 100 m / s - 6 m / s ) t

= > 8 m = t( 6 m / s + 50 m / s - 3 m / s )

= > 8 m = t( 53 m / s )

= > 8 / 53 s

Therefore :

= > Force = Mass x Acceleration

= > Force = 200 kg x ( 100 m / s - 6 m / s ) / ( 8 / 53 s )

= > Force = 200 x ( 94 x 53 ) / 8 N

= > Force = 25 x 94 x 53 N

= > Force = 124,550 N

Hence the required force is 124,550 N.