Waylon played defense in 12 soccer games. This was 60% of the total number of games he played. How many games did Waylon play?
Answers
Answered by
6
Answer:
20
Step-by-step explanation:
total number of games =x
defense percentage =60%
defense games =12
so,
60% of x is 12
60/100Xx=12
6x=120
x=120/6
x=20
cross check:
60/100x20=12
60/5=12
12=12
hence LHS=RHS
Answered by
5
Answer:
20
Step-by-step explanation:
Let the total number of games played by Waylon be x.
Defence percentage =60%
Defence in games = 12
according to the given question....
60% of x = 12
=>60/100 × (x) = 12
x = 12 × 100/60
x = 20
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