Math, asked by acharyvikash7624, 11 months ago

Waylon played defense in 12 soccer games. This was 60% of the total number of games he played. How many games did Waylon play?

Answers

Answered by priyaa1310
6

Answer:

20

Step-by-step explanation:

total number of games =x

defense percentage =60%

defense games =12

so,

60% of x is 12

60/100Xx=12

6x=120

x=120/6

x=20

cross check:

60/100x20=12

60/5=12

12=12

hence LHS=RHS

Answered by Shraddha02004
5

Answer:

20

Step-by-step explanation:

Let the total number of games played by Waylon be x.

Defence percentage =60%

Defence in games = 12

according to the given question....

60% of x = 12

=>60/100 × (x) = 12

x = 12 × 100/60

x = 20

Similar questions