WB JEE (Engineering). Solved Paper 2
52. The minimum value of the function
f(x)=2x-1| +Ix-2lis
(a) 0 (0) 1 (0) 2 (d) 3.
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Answer:(d) 3
Explanation:since modulus is taken so no negative value can be taken as it will increase the net value.
So put x=0 or 2 and we get 3
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