Question

We are 10 C1050
7. A body covers half of its journey need of
of 60 ms and the other half with
40 ms -1. Then find the average speed
whole journey
1 anods up to
half with a speed of
average speed during the​

Answer 1

$t1 = \frac{s}{60 \times 2} = \frac{s}{120} \\ t2 = \frac{2}{80} \\ total \: distance = s \\ total \: time = t1 + t2 \\ avg \: speed = \frac{total \: distance}{total \: time} \\ avg \: speed = \frac{s}{ \frac{s}{120} + \frac{s}{80} } = \frac{9600}{200} = 48 \frac{km}{hr}$

i hope this helps ( ╹▽╹ )