Question

We are trying to factorize (8x^3−y^3−z^3−6xyz)
this is what we get: (2x+Py-Qz)(4x^2+y^2+z^2+Rxy−yz+2zx)
find P, Q and R

Answer 1

$\tt \: (8x^3−y^3−z^3−6xyz)$

$\:$

Solution:

$\tt8x^{3}-6yzx-y^{3}-z^{3}$

$\tt\left(2x-y-z\right)\left(4x^{2}+2xy+2xz+y^{2}-yz+z^{2}\right)$

Therefore,

• P=O
• Q=0
• R=2

$\:$

CelestialCentrix

Answer 2

Step-by-step explanation:

We are trying to factorize (8x^3−y^3−z^3−6xyz)

this is what we get: (2x+Py-Qz)(4x^2+y^2+z^2+Rxy−yz+2zx)

find P, Q and R