Question

We area of a quadrilateral whose diagonal measures 24 cm and the lengths of the perpendiculars
on it from the opposite vertices are 6.4 cm and 7.6 cm respectively.
- Find the area of the given​

Answer 1

Step-by-step explanation:

Area of a quadrilateral - 1/2 ×diagonal ×length of perpendicular

1/2 ×24×6.4 ×7.5

12×6.4×7.5(cancelling 2 and 24)

=576

HOPE IT HELPS!!!

Answer 2

Area of quadrilateral ABCD=168$cm^2$

Step-by-step explanation:

Length of diagonal BD=24 cm

Length of perpendicular AP=7.6 cm

Length of perpendicular CQ=6.4 cm

Area of triangle=$\frac{1}{2}\times b\times h$

Where b= Base of triangle

h=Height of triangle

Using the formula then we get

Area of triangle ABD=$\frac{1}{2}\times 24\times 7.6=91.2 cm^2$

Area of triangle BCD=$\frac{1}{2}\times 24\times 6.4=76.8 cm^2$

Area of quadrilateral ABCD= Area of triangle ABD+area of triangle BCD

Area of quadrilateral ABCD=91.2+76.8=168$cm^2$

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https://brainly.in/question/7639700:Answered by Brainly user